Optimal. Leaf size=166 \[ \frac{8 (83 A-20 B) \sin (c+d x)}{105 a^4 d}-\frac{(4 A-B) \sin (c+d x)}{a^4 d (\sec (c+d x)+1)}-\frac{(88 A-25 B) \sin (c+d x)}{105 a^4 d (\sec (c+d x)+1)^2}-\frac{x (4 A-B)}{a^4}-\frac{(12 A-5 B) \sin (c+d x)}{35 a d (a \sec (c+d x)+a)^3}-\frac{(A-B) \sin (c+d x)}{7 d (a \sec (c+d x)+a)^4} \]
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Rubi [A] time = 0.572593, antiderivative size = 166, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.138, Rules used = {4020, 3787, 2637, 8} \[ \frac{8 (83 A-20 B) \sin (c+d x)}{105 a^4 d}-\frac{(4 A-B) \sin (c+d x)}{a^4 d (\sec (c+d x)+1)}-\frac{(88 A-25 B) \sin (c+d x)}{105 a^4 d (\sec (c+d x)+1)^2}-\frac{x (4 A-B)}{a^4}-\frac{(12 A-5 B) \sin (c+d x)}{35 a d (a \sec (c+d x)+a)^3}-\frac{(A-B) \sin (c+d x)}{7 d (a \sec (c+d x)+a)^4} \]
Antiderivative was successfully verified.
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Rule 4020
Rule 3787
Rule 2637
Rule 8
Rubi steps
\begin{align*} \int \frac{\cos (c+d x) (A+B \sec (c+d x))}{(a+a \sec (c+d x))^4} \, dx &=-\frac{(A-B) \sin (c+d x)}{7 d (a+a \sec (c+d x))^4}+\frac{\int \frac{\cos (c+d x) (a (8 A-B)-4 a (A-B) \sec (c+d x))}{(a+a \sec (c+d x))^3} \, dx}{7 a^2}\\ &=-\frac{(A-B) \sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac{(12 A-5 B) \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}+\frac{\int \frac{\cos (c+d x) \left (2 a^2 (26 A-5 B)-3 a^2 (12 A-5 B) \sec (c+d x)\right )}{(a+a \sec (c+d x))^2} \, dx}{35 a^4}\\ &=-\frac{(88 A-25 B) \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac{(A-B) \sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac{(12 A-5 B) \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}+\frac{\int \frac{\cos (c+d x) \left (a^3 (244 A-55 B)-2 a^3 (88 A-25 B) \sec (c+d x)\right )}{a+a \sec (c+d x)} \, dx}{105 a^6}\\ &=-\frac{(88 A-25 B) \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac{(A-B) \sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac{(12 A-5 B) \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac{(4 A-B) \sin (c+d x)}{d \left (a^4+a^4 \sec (c+d x)\right )}+\frac{\int \cos (c+d x) \left (8 a^4 (83 A-20 B)-105 a^4 (4 A-B) \sec (c+d x)\right ) \, dx}{105 a^8}\\ &=-\frac{(88 A-25 B) \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac{(A-B) \sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac{(12 A-5 B) \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac{(4 A-B) \sin (c+d x)}{d \left (a^4+a^4 \sec (c+d x)\right )}+\frac{(8 (83 A-20 B)) \int \cos (c+d x) \, dx}{105 a^4}-\frac{(4 A-B) \int 1 \, dx}{a^4}\\ &=-\frac{(4 A-B) x}{a^4}+\frac{8 (83 A-20 B) \sin (c+d x)}{105 a^4 d}-\frac{(88 A-25 B) \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac{(A-B) \sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac{(12 A-5 B) \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac{(4 A-B) \sin (c+d x)}{d \left (a^4+a^4 \sec (c+d x)\right )}\\ \end{align*}
Mathematica [B] time = 1.03939, size = 485, normalized size = 2.92 \[ \frac{\sec \left (\frac{c}{2}\right ) \cos \left (\frac{1}{2} (c+d x)\right ) \left (-7350 d x (4 A-B) \cos \left (c+\frac{d x}{2}\right )-7350 d x (4 A-B) \cos \left (\frac{d x}{2}\right )-46130 A \sin \left (c+\frac{d x}{2}\right )+46116 A \sin \left (c+\frac{3 d x}{2}\right )-18060 A \sin \left (2 c+\frac{3 d x}{2}\right )+19292 A \sin \left (2 c+\frac{5 d x}{2}\right )-2100 A \sin \left (3 c+\frac{5 d x}{2}\right )+3791 A \sin \left (3 c+\frac{7 d x}{2}\right )+735 A \sin \left (4 c+\frac{7 d x}{2}\right )+105 A \sin \left (4 c+\frac{9 d x}{2}\right )+105 A \sin \left (5 c+\frac{9 d x}{2}\right )-17640 A d x \cos \left (c+\frac{3 d x}{2}\right )-17640 A d x \cos \left (2 c+\frac{3 d x}{2}\right )-5880 A d x \cos \left (2 c+\frac{5 d x}{2}\right )-5880 A d x \cos \left (3 c+\frac{5 d x}{2}\right )-840 A d x \cos \left (3 c+\frac{7 d x}{2}\right )-840 A d x \cos \left (4 c+\frac{7 d x}{2}\right )+60830 A \sin \left (\frac{d x}{2}\right )+16520 B \sin \left (c+\frac{d x}{2}\right )-14280 B \sin \left (c+\frac{3 d x}{2}\right )+7560 B \sin \left (2 c+\frac{3 d x}{2}\right )-5600 B \sin \left (2 c+\frac{5 d x}{2}\right )+1680 B \sin \left (3 c+\frac{5 d x}{2}\right )-1040 B \sin \left (3 c+\frac{7 d x}{2}\right )+4410 B d x \cos \left (c+\frac{3 d x}{2}\right )+4410 B d x \cos \left (2 c+\frac{3 d x}{2}\right )+1470 B d x \cos \left (2 c+\frac{5 d x}{2}\right )+1470 B d x \cos \left (3 c+\frac{5 d x}{2}\right )+210 B d x \cos \left (3 c+\frac{7 d x}{2}\right )+210 B d x \cos \left (4 c+\frac{7 d x}{2}\right )-19880 B \sin \left (\frac{d x}{2}\right )\right )}{1680 a^4 d (\cos (c+d x)+1)^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.1, size = 229, normalized size = 1.4 \begin{align*} -{\frac{A}{56\,d{a}^{4}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{7}}+{\frac{B}{56\,d{a}^{4}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{7}}+{\frac{7\,A}{40\,d{a}^{4}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{5}}-{\frac{B}{8\,d{a}^{4}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{5}}-{\frac{23\,A}{24\,d{a}^{4}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}+{\frac{11\,B}{24\,d{a}^{4}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}+{\frac{49\,A}{8\,d{a}^{4}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }-{\frac{15\,B}{8\,d{a}^{4}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }+2\,{\frac{A\tan \left ( 1/2\,dx+c/2 \right ) }{d{a}^{4} \left ( 1+ \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) }}-8\,{\frac{A\arctan \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) }{d{a}^{4}}}+2\,{\frac{\arctan \left ( \tan \left ( 1/2\,dx+c/2 \right ) \right ) B}{d{a}^{4}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.52736, size = 366, normalized size = 2.2 \begin{align*} \frac{A{\left (\frac{1680 \, \sin \left (d x + c\right )}{{\left (a^{4} + \frac{a^{4} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}{\left (\cos \left (d x + c\right ) + 1\right )}} + \frac{\frac{5145 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{805 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{147 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac{15 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}}{a^{4}} - \frac{6720 \, \arctan \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{4}}\right )} - 5 \, B{\left (\frac{\frac{315 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{77 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{21 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac{3 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}}{a^{4}} - \frac{336 \, \arctan \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{4}}\right )}}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.486195, size = 574, normalized size = 3.46 \begin{align*} -\frac{105 \,{\left (4 \, A - B\right )} d x \cos \left (d x + c\right )^{4} + 420 \,{\left (4 \, A - B\right )} d x \cos \left (d x + c\right )^{3} + 630 \,{\left (4 \, A - B\right )} d x \cos \left (d x + c\right )^{2} + 420 \,{\left (4 \, A - B\right )} d x \cos \left (d x + c\right ) + 105 \,{\left (4 \, A - B\right )} d x -{\left (105 \, A \cos \left (d x + c\right )^{4} + 4 \,{\left (296 \, A - 65 \, B\right )} \cos \left (d x + c\right )^{3} + 4 \,{\left (659 \, A - 155 \, B\right )} \cos \left (d x + c\right )^{2} +{\left (2236 \, A - 535 \, B\right )} \cos \left (d x + c\right ) + 664 \, A - 160 \, B\right )} \sin \left (d x + c\right )}{105 \,{\left (a^{4} d \cos \left (d x + c\right )^{4} + 4 \, a^{4} d \cos \left (d x + c\right )^{3} + 6 \, a^{4} d \cos \left (d x + c\right )^{2} + 4 \, a^{4} d \cos \left (d x + c\right ) + a^{4} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32156, size = 257, normalized size = 1.55 \begin{align*} -\frac{\frac{840 \,{\left (d x + c\right )}{\left (4 \, A - B\right )}}{a^{4}} - \frac{1680 \, A \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )} a^{4}} + \frac{15 \, A a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 15 \, B a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 147 \, A a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 105 \, B a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 805 \, A a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 385 \, B a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 5145 \, A a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1575 \, B a^{24} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a^{28}}}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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